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Harry Potter Problem


Here's some dialogue from Harry Potter and the Sorcerer's Stone.

quotes = """Molly Weasley: Fred, you next.
George Weasley: He’s not Fred, I am!
Fred Weasley: Honestly, woman. You call yourself our mother.
Molly Weasley: Oh, I’m sorry, George.
Fred Weasley: I’m only joking, I am Fred!"""

Identify each line spoken by Fred. Then put them in a list. (Note that quotes is a multi-line string.)

Expected result
lines = [
    'Fred Weasley: Honestly, woman. You call yourself our mother.', 
    'Fred Weasley: I’m only joking, I am Fred!'
]
Regex Functions
Function Description Return Value
re.findall(pattern, string, flags=0) Find all non-overlapping occurrences of pattern in string list of strings, or list of tuples if > 1 capture group
re.finditer(pattern, string, flags=0) Find all non-overlapping occurrences of pattern in string iterator yielding match objects
re.search(pattern, string, flags=0) Find first occurrence of pattern in string match object or None
re.split(pattern, string, maxsplit=0, flags=0) Split string by occurrences of pattern list of strings
re.sub(pattern, repl, string, count=0, flags=0) Replace pattern with repl new string with the replacement(s)
Regex Patterns
Pattern Description
[abc] a or b or c
[^abc] not (a or b or c)
[a-z] a or b ... or y or z
[1-9] 1 or 2 ... or 8 or 9
\d digits [0-9]
\D non-digits [^0-9]
\s whitespace [ \t\n\r\f\v]
\S non-whitespace [^ \t\n\r\f\v]
\w alphanumeric [a-zA-Z0-9_]
\W non-alphanumeric [^a-zA-Z0-9_]
. any character
x* zero or more repetitions of x
x+ one or more repetitions of x
x? zero or one repetitions of x
{m} m repetitions
{m,n} m to n repetitions
{m,n} m to n repetitions
\\, \., \* backslash, period, asterisk
\b word boundary
^hello starts with hello
bye$ ends with bye
(...) capture group
(po|go) po or go

Try with Google Colab See the solution